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Johnny G · Answer 1 · 2023-10-02T14:58:04+0000

According to Work energy theorem,

$W=(1)/(2)mv^2-(1)/(2)mu^{2^{}^{}}^{}$

Finally, the car comes at rest therefore,

$v=0\text{ m/s}$

Substitute the given value in the equation of work-energy theorem,

$\begin{gathered} W=(1)/(2)(1175kg)(0m/s)^2(\frac{1\text{ J}}{1kgm^2s^(-2)})-(1)/(2)(1175\text{ kg)(}125km/h)^2(\frac{1000\text{ m}}{1\text{ km}})^2(\frac{1\text{ h}}{60\text{ min}})^2(\frac{1\text{ min}}{60\text{ s}})^2(\frac{1\text{ J}}{1kgm^2s^(-2)}) \\ =0\text{ J-}708309\text{ J} \\ =-708309\text{ J} \end{gathered}$

Thus, the magnitude of work done to stop the car is 708309 J.

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