Question

Find the mass of a sample of water if its temperature dropped 19.7 °C when it lost 6008 J of heat. Water = 4.18 J/gºC

Answer 1

The mass of the sample is 72.96 grams

Step-by-step explanation

Given that;

The heat lost is 6008 J

The temperature drop of the sample - 19.7 degrees Celcius

The specific heat capacity of water is 4.18J/g degrees Celcius

Follow the steps below to find the mass of the sample

Step 1; Write the formula for heat energy

`\begin{gathered} \text{ q = mc}\Delta T \\ \text{ Make m the subject of the formula} \\ \text{ m = }\frac{\text{ q}}{\text{ c}\Delta T} \end{gathered}`

Step 2; Substitute the given data into the formula in step 1

`\begin{gathered} \text{ m = }\frac{-6008}{\text{ 4.18}*(-19.7)} \\ \\ \text{ m = }\frac{\text{ -6008}}{\text{ - 82.346}} \\ \text{ m = 72.96 grams} \end{gathered}`

Therefore, the mass of the sample is 72.96 grams