Step 1: Use the equation ratio between Al and AlCl3 to discover the number of moles of AlCl3 produced.
The equation is: 2Al+3Cl2 -->2AlCl3
So 2 moles of Al produces 2 moles of AlCl3.
Step 2: Transform 2 moles of AlCl3 using the following formula: mass = moles x molar mass
the molar mass of AlCl3 is:
Molar mass of Al: 26.98 g/mol
Molar mass of Cl: 35.45 g/mol
Molar mass of AlCl3: (26.98*1) + (35.45*3) = 133.34 g/mol
So:
mass = moles x molar mass
mass = 2 * 133.34 = 266.68 g
Answer: 266.68 g