In order to determine the values of the numbers, it is necessary to write the given situation in an algebraic way:
one number is 1 more than 3 times a second number:
x = 1 + 3y
4 more than 2 times the first number is decreased by 3 times the second number the result is 60:
4 + 2x - 3y = 60
Then, you have a system of equations, that you can write as follow:
x - 3y = 1
2x - 3y = 56
To solve the previous system, you can subtract the second eequation to the first one, and solve for x:
x - 3y = 1
-2x + 3y = -56
-x = -55
x = 55
Next, you replace the previous value of x into the equation x - 3y = 1, and solve for y:
55 - 3y = 1
-3y = 1-55
-3y = -54
y = -54/(-3)
y = 18
Hence, the solution to the system of equations is:
x = 55
y = 18