Question

Find the 32nd term of 7,13,19

Answer 1

The sequence given:

7, 13, 19, ...

This is an arithmetic sequence.

The first term (a1) is 7.

The common difference (d) between the terms is 13 - 7 =6, or 19 - 13 = 6.

To find the 32nd term of this sequence, we are going to use the nth term formula of an arithmetic sequence, shown below:

`a_n=a_1+(n-1)d`

Where

a_n is the nth term

a_1 is the first term

n is the number of the term

d is the common difference

Given,

a_1 = 7

d = 6

Let us find the 32nd term:

`\begin{gathered} a_n=a_1+(n-1)d \\ a_(32)=7+(32-1)(6) \\ a_(32)=7+31(6) \\ a_(32)=7+186 \\ a_(32)=193 \end{gathered}`

Thus, the 32nd term of this arithmetic sequence is 193.

Answer

193