Recall the formula for determining the interest using simple interest
![\begin{gathered} I=Prt \\ \text{where} \\ P\text{ is the principal amount} \\ r\text{ is the rate in decimal form} \\ t\text{ is time} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/897sql3ucis5eccspfcgorajjea5lgih8b.png)
Convert the rate into decimal form by dividing by 100%
![7\%/100\%=0.07](https://img.qammunity.org/2023/formulas/mathematics/high-school/8agv6ibcfnnyggn3relbysv9vz0an7w8uz.png)
Substitute the following values
P = $1300, r = 0.07, t = 6/12 (12 months in a year, only 6 months has passed)
![\begin{gathered} I=Prt \\ I=1300\cdot0.07\cdot(6)/(12) \\ I=91\cdot(1)/(2) \\ I=45.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/l43ajxvbuwsgc7l4ja0mpxfuce10mnhoth.png)
Therefore, Margo will pay back $45.50 in interest.