8 people fit comfortably in a 6 ft. by 6 ft. area. Usethis value to estimate the size of crowds of 2 sidesthat is 2 yards deep and 3 miles long.

Question

asked Apr 23, 2023 219k views

1 Answer

RiverHeart · Answer 1 · 2023-04-28T11:51:48+0000

For this problem we can start estimating the area for the 8 people

$A=\text{ 6ft}\cdot6ft=36ft^2$

And we also know that 8 people fit on this area

Then we can find the total area for the new structure (A1) but first we need to convert first 2yd to ft and 3 mi to ft, we know that:

1 yd= 3ft and 1 mi = 5280 ft.

$\text{ 2yd}\cdot(3ft)/(1yd)=\text{ 6 ft, 3 mi }\cdot\frac{5280\text{ ft}}{1mi}=\text{ 15840 ft}$

$A_{1\text{ }}=2\cdot6ft\cdot15480ft=190080ft^2\text{ }$

And then we can use a proportional rule given by:

$\frac{8\text{ people}}{36ft^2}=\text{ }(x)/(190080ft^2)$

And solving for x we got:

$x=190080ft^2\cdot\text{ }\frac{8\text{ people}}{36ft^2}=\text{ 42240 people}$

And for this case the final answer would be 42240 people