Let be "x" the number of bottles of sparkling water that the company produces when it produces 600 bottles of plain water.
a. You know that the factory produces 3 bottles of sparkling water for every 8 bottles of plain water.
Therefore, knowing that it produces 600 bottles of plain water, you can write the following proportion:
![(3)/(8)=(s)/(600)](https://img.qammunity.org/2023/formulas/mathematics/college/zn2yg0aw95v5ogvdd40paw5ra5kepnux4k.png)
Solve for "s" :
![\begin{gathered} ((3)/(8))(600)=x \\ \\ (1800)/(8)=x \\ \\ x=225 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/habh3qt64zbm8xz4lxxu673x4oz7z0np27.png)
b. Knowing that the ratio is:
![3\colon8](https://img.qammunity.org/2023/formulas/mathematics/college/qfp4fuge8wlz7o6ngwkz6aiaiq46s8b9hc.png)
You can set up the following equation:
![\begin{gathered} 3s=8p \\ \\ s=(8)/(3)p \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/axva8nwecrmn3skxbejp0rkq7qa4fam560.png)
Where "s" is the number of bottles of sparkling and "p" is the number of bottles of plain water.
Therefore, the answers are:
a. 225 bottles of sparkling water.
b.
![s=(8)/(3)p](https://img.qammunity.org/2023/formulas/mathematics/college/wxfvqbkwmrwl0dlod4n06qvqedwhlau3im.png)