Question

A painter measures a wall and determines it is 4.2 m by 3.3 m. high. The room is square and has a door that is 2 m x 1 m and two windows that are each 1.5 m x 1.5 m. How many yd2 of wall space needs to be painted? (1 m = 1.1yd)

Answer 1

The room is square, it means it has 4 walls with same dimentions. Let's calculate the area of one of them.

`A_w=4.2*3.3=13.86m^(2)`

The total area is:

`A_(4w)=4*13.86=55.44m^(2)`

If we calculate now the area of each window and of the door, we just need to subtract these values from the total of the 4 walls to find the area that needs to be painted.

`\begin{gathered} A_d=2*1=2m^(2) \\ A_(win)=1.5*1.5=2.25m^2\to A_(2win)=4.5m^(2) \end{gathered}`

The area to be painted is:

`A_p=A_w-A_(2win)-A_d=55.44-2-4.5=48.94m^(2)`

To change it from m² to yd², we need to multiply it to 1.21, it is:

`A_p=48.94*1.21=59.2174yd^(2)`

The answer is: 59.23yd²