Question

Solve for x for an exponential equation of 5^(x-2) + 5^(x+1) = 126

Answer 1

H+5x5= 1265*(7+5) = 126
5° (14125) = 126
57 x 끓을= 126
5T = 25
55 = 52

Answer 2

The expression is given as

`5^(x-2)+5^(x+1)=126`

Solve for x.

`(5^x)/(5^2)+5^x*5=126`
`5^x((1)/(25)+5)=126`
`5^x((1+125)/(25))=126`
`5^x*(126)/(25)=126`
`5^x=25`
`5^x=5^2`

Compare the power and find the value of x.

`x=2`

Hence the value of x is 2.