We are given the following information concerning the three production machines;

Also, we are given the percentage of defective output as follows;

Therefore, if an item is selected randomly, the probability that the item is defective would be;
![\begin{gathered} P\lbrack defective\rbrack=(0.55*0.035)+(0.25*0.045)+(0.20*0.055) \\ P\lbrack\text{defective\rbrack}=0.01925+0.01125+0.011 \\ P\lbrack\text{defective\rbrack}=0.0415 \end{gathered}]()
ANSWER:
The probability that the item is defective would be 0.0415