![\mathbf{x}^{\mathbf{(7)/(6)}}](https://img.qammunity.org/2023/formulas/mathematics/college/62mtc051he79p756rp1l074qjd8j9hvvla.png)
1) Let's simplify the following product:
![x^{(1)/(2)}\cdot x^{(2)/(3)}](https://img.qammunity.org/2023/formulas/mathematics/college/rfs6nc4as1fxgarydmfgvm4q4aboocj9vk.png)
Note that, we can simplify this using the exponent's properties.
2) So we can keep the base and add the exponents:
![x^{(1)/(2)}\cdot x^{(2)/(3)}=x^{(3+4)/(6)}=x^{(7)/(6)}](https://img.qammunity.org/2023/formulas/mathematics/college/dqoj12mgg2f04nbpeo9arvnc391klg0rvr.png)
Note that since the denominators were different, we had to resort to the LCM of 2 and 3 and simplify it to one fraction.
3) Hence, the answer is:
![\mathbf{x}^{\mathbf{(7)/(6)}}](https://img.qammunity.org/2023/formulas/mathematics/college/62mtc051he79p756rp1l074qjd8j9hvvla.png)