73.2k views
4 votes
X^1/2 x X^2/3Simplify

User WhatsUp
by
3.8k points

1 Answer

5 votes

\mathbf{x}^{\mathbf{(7)/(6)}}

1) Let's simplify the following product:


x^{(1)/(2)}\cdot x^{(2)/(3)}

Note that, we can simplify this using the exponent's properties.

2) So we can keep the base and add the exponents:


x^{(1)/(2)}\cdot x^{(2)/(3)}=x^{(3+4)/(6)}=x^{(7)/(6)}

Note that since the denominators were different, we had to resort to the LCM of 2 and 3 and simplify it to one fraction.

3) Hence, the answer is:


\mathbf{x}^{\mathbf{(7)/(6)}}

User Jviotti
by
3.2k points