Question

4.5 ft wide and 6 feet long and 2 ft longer and 1.5 feet wider. how do I solve this

Answer 1

`B)48\text{ sq ft}`

Step-by-step explanation

the area of a rectangle is given by:

`A_(rec\tan gle)=length\cdot width`

Step 1

Set the new measures

`\begin{gathered} \text{length}_(new)=6+2=8\text{ ft} \\ \text{width}_(new)=4.5+1.5=6\text{ ft} \end{gathered}`

Step 2

replace in the formula to find the new area

`\begin{gathered} A_(rec\tan gle)=length\cdot width \\ A_(rec\tan gle)=8\text{ ft}\cdot\text{ 6 ft} \\ A_(rec\tan gle)=48\text{ sq ft} \\ \end{gathered}`

so,the answer is

`B)48\text{ sq ft}`

I hope this helps you