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Need help asap NO THIS IS NOT A QUIZ , ASSESSMENT OR TEST.

Need help asap NO THIS IS NOT A QUIZ , ASSESSMENT OR TEST.-example-1

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From the diagram, the required length of the entire tunnel is (m + n) meters

In triangle ADC,

opposite = m

hypotenuse = 340


\begin{gathered} \sin \text{58 =}(m)/(340) \\ m\text{ = 340 x sin58} \\ m=288.336m \end{gathered}

In triangle BCD,

opposite = n

Hypotenuse = 193


\begin{gathered} \sin 21=(n)/(193) \\ n=193\sin 21 \\ n=69.165m \end{gathered}

The length of the tunnel is

288.336m + 69.165m

=357.501m

=357.5m ( nearest tenth)

The answer is 357.5m ( nearest tenth)

Need help asap NO THIS IS NOT A QUIZ , ASSESSMENT OR TEST.-example-1
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