Question

Table of values! I’m mixing up negative and minus signs in my coculator PLEASE HELP

Answer 1

Given,

The function is,

`f(x)=-x^2-5x+4`

Subtituting x = -5 then,

`\begin{gathered} f(-5)=-(-5)^2-5(-5)+4 \\ =-25+25+4 \\ =4 \end{gathered}`

Subtituting x = -4 then,

`\begin{gathered} f(-4)=-(-4)^2-5(-4)+4 \\ =-16+20+4 \\ =8 \end{gathered}`

Subtituting x = -3 then,

`\begin{gathered} f(-3)=-(-3)^2-5(-3)+4 \\ =-9+15+4 \\ =10 \end{gathered}`

Subtituting x = -2 then,

`\begin{gathered} f(-2)=-(-2)^2-5(-2)+4 \\ =-4+10+4 \\ =10 \end{gathered}`

Subtituting x = -1 then,

`\begin{gathered} f(-1)=-(-1)^2-5(-1)+4 \\ =-1+5+4 \\ =8 \end{gathered}`

Subtituting x =0 then,

`\begin{gathered} f(0)=-(0)^2-5(0)+4 \\ =4 \end{gathered}`

Subtituting x = 1 then,

`\begin{gathered} f(1)=-(1)^2-5(1)+4 \\ =-1-5+4 \\ =-2 \end{gathered}`

Subtituting x = 2 then,

`\begin{gathered} f(2)=-(2)^2-5(2)+4 \\ =-4-10+4 \\ =-10 \end{gathered}`

Hence, the output of the different inputs of the function is obtained.