Hello there. To solve this question, we have to remember some properties about probabilities.
Given that buying a pair of shoes and buying a book are independent events and the probability a shopper buys shoes is 0.12 and the probability that a shopper buys a book is 0.10, we want to determine:
The probability that a shopper buys shoes and a book.
For this, say that the events
![\begin{gathered} A:\text{ shopper buys shoes} \\ B:\text{ shopper buys a book} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xx0cn4yziad1qmhvv0675381tm2fop5gd9.png)
They are independent, which means that
![A\cap B=\emptyset](https://img.qammunity.org/2023/formulas/mathematics/college/j15i65gxfgazt02uvzirbfgi0zgen57b3t.png)
But we're looking for the probability of the shopper buying shoes and a book, therefore the probability of the intersection of events is not zero.
We use the conditional probability to prove that
![P(A\cap B)=P(A)\cdot P(B)](https://img.qammunity.org/2023/formulas/mathematics/college/hl6jg1edts8gn0tgzn8avhzzh4ntw7ayxm.png)
Hence we have that
![P(A\cap B)=0.12\cdot0.10](https://img.qammunity.org/2023/formulas/mathematics/college/w1i1pal8dgbi5l40e33uz6r7en8mc96eol.png)
Multiplying the numbers gives you
![P(A\cap B)=0.012](https://img.qammunity.org/2023/formulas/mathematics/college/olih0krzvun11jboocjuke29zg38di87ho.png)
This is the answer to this question and it is contained in the last option.