Question

find the surface area of square pyramid with base edges of 8 feet the height of each lateral is 9 feet

Answer 1

Answer:

Explanations:

The surface area of a square based pyramid is given by the formula:

`\begin{gathered} A\text{ = }a^2+2a\sqrt[]{(a^2)/(4)+h^2}^{} \\ \text{Where a = base edge } \\ h\text{ = lateral height} \end{gathered}`

From the question:

a = 8 feet

h = 9 feet

Substitute the values of a and h into the given formula for surface area:

`\begin{gathered} A=8^2+2(8)\sqrt[]{(8^2)/(4)+9^2} \\ A\text{ = 64 + 16}\sqrt[]{(64)/(4)+81} \\ A\text{ = 64 + 16}\sqrt[]{16+81} \\ A\text{ = 64+16}\sqrt[]{97} \\ A\text{ =}64+157.58 \\ A\text{ = }221.58ft^2 \end{gathered}`