Question

(x+y)^2 -37 evaluate if x =4 and y = -9

Answer 1

Given:

`(x+y)^2-37`

To find: Evalute if x =4 and y = -9?

Solution:

We have given that

`=(x+y)^2-37\ldots\text{.}\mathrm{}(1)`

Here, we use the identity

`(a+b)^2=a^2+2ab+b^2`

Eq.1 becomes

`=x^2+2xy+y^2-37`

Now, substitute x = 4 and y = -9

We get,

`\begin{gathered} =(4)^2+2(4)(-9)+(-9)^2-37 \\ \\ =16-72+81-37 \\ \\ =81+16-37-72 \\ \\ =97-109 \\ \\ =-12 \end{gathered}`

Hence, (x+y)^2 -37 = -12 if x =4 and y = -9

Thus, (x+y)^2 -37 = -12 if x = 4 and y = -9.