2 LiCl + Pb(NO3)2 => PbCl2 + 2 LiNO3 (already balanced)
We already have 6.6 g PbCl2, but we want to know how many grams of LiNO3 are also produced.
Procedure:
Molar masses:
PbCl2 => 278 g/mol
LiNO3 => 68 g/mol
278 g PbCl2 ---- 2 x 68 g LiNO3
6.6 g PbCl2----- X
X = (6.6 g x 2 x 68 g)/278 g = 3.2 g
Answer: 3.2 g LiNO3 produced