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Given v = 520 sin (30t - 5π/4), what is the frequency?Question 13 options:15 Hz30 Hz4.8 Hz19.1 Hz

User Vladan
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1 Answer

3 votes

a The frequency of the sin(x) depends on the period

If the wave has period = 2pi, then the frequency is 1

The frequency of sin(2x) is 2

The given equation is


v=520\sin (30t-(5\pi)/(4))

Since the frequency = 2pi/period

Since the period = 2pi/30 = pi/15

Then


\begin{gathered} F=(2\pi)/((\pi)/(15)) \\ F=2\pi*(15)/(\pi) \\ F=2*15 \\ F=30\text{ HZ} \end{gathered}

The frequency is 30 Hz

The answer is B

User Infinitezero
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