60.0k views
4 votes
Problem Set B: For #1 and #2, solve the equation using the guide of the boxes, then confirm that your solution is correct using the graph provided. 1. Solve xl - 2 = 3x + 2 2. Solve (2x - 11 -2 = -x

User Tameshwar
by
7.9k points

1 Answer

5 votes

Question 1:

Adding 2 to both sides of the equation gives


|x|=3x+4

Now, the absolute value decomposes the above equation into two separate equations


\begin{gathered} x=3x+4 \\ x=-3x-4 \end{gathered}

The first equation gives


\begin{gathered} x=3x+4 \\ -2x=4 \\ \boxed{x=-2} \end{gathered}

The second equation gives


\begin{gathered} x=-3x-4 \\ 4x=-4 \\ \boxed{x=-1} \end{gathered}

The graph of the system is

We see that the solutions exists at x =-1.

Question 2.

Adding 2 to both sides of the equation gives


|2x-1|=-x+2

Decomposing the absolute value on LHS gives us two equations


\begin{gathered} -(2x-1)=-x+2 \\ 2x-1=-x+2 \end{gathered}

Solving the first equation gives


\begin{gathered} 2x-1=x-2 \\ x=-1 \end{gathered}

Solving the second equation gives


\begin{gathered} 2x-1=-x+2 \\ 3x=3 \\ x=1 \end{gathered}

Hence, the solution to the equation is


x=\pm1

The graph of the solutions is

We see that the solution is at x = -1 and x = 1; hence, our solution is confirmed.

Problem Set B: For #1 and #2, solve the equation using the guide of the boxes, then-example-1
Problem Set B: For #1 and #2, solve the equation using the guide of the boxes, then-example-2
User Lukas Risko
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories