Question

I am unsure how to solve for A= and to draw the graph

Answer 1

`\begin{gathered} y=3(x+2)^2\text{ - 8} \\ \end{gathered}`

From the general equation of a parabola

`y=a(x-h)^2\text{ + k}`

a = 3

The parabola will open up because it is positive.

The parabola has a minimum

The axis of symmetry is at x = -2

Vertex = (-2, -8)

y - intercept (0, 4)

The equation of the graph

y = 3 (x+2)(x+2) - 8

= 3( x^2 +4x +4) - 8

= 3x^2 +12x+12-8

y= 3x^2 +12x +4