Question

How many fluorine atoms are present in 5.36 g of C2F4?

Answer 1

1) Convert grams to moles

the molar mass of C2F4 is 100.0150 g/mol

`molC_2F_4=5.36gC_2F_4\cdot(1molC_2F_4)/(100.0150gC_2F_4)=0.05359molC_2F_4`

2) Convert moles of C2F4 to moles of F

F to C2F4 ratio

4 atoms of F: 1 molecule of C2F4

`molF_{}=0.05359molC_2F_4\cdot\frac{4molF_{}}{1molC_2F_4}=0.21436molF`

3) Convert moles of F to atom units of F

Avogadro's number is 6.022*10^23

`atomsF_{}=0.21436molF\cdot\frac{6.022\cdot10^(23)atoms\text{ F}}{1molF_{}}_{}=1.291\cdot10^(23)\text{atoms F}`

There are 1.291*10^23 atoms of Fluorine in 5.36 g of C2F4.