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Find the measure of one exterior angle of a regular polygon whose sum of the interior angles is 2340

User Wilmer SH
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3 votes

Answer:


\text{ One of the exterior angles is 204}\degree

Explanation:

The interior angles of any polygon are represented by the following equation:


(n-2)\cdot180=\sum \text{interior}

If the sum of the interior angles is 2340, solve for n to determine how many vertices it has:


\begin{gathered} (n-2)\cdot180=2340 \\ n-2=(2340)/(180) \\ n=13+2 \\ n=15 \end{gathered}

Now, if the polygon has 15 vertices. Use the equation for the sum of exterior angles, which is represented as:


\begin{gathered} (n+2)\cdot180 \\ =(15+2)\cdot180 \\ =17\cdot180 \\ =3060 \end{gathered}

If it is a regular polygon, each angle measures the same:


\begin{gathered} (3060)/(15)=204\degree \\ \text{ One of the exterior angles is 204}\degree \end{gathered}

User Dan Russell
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