Question

If the maximum moment of force on a door is 10 Nm by an applied force of 2.25 N, then the distance of handle

Answer 1

d = 4.44 m

Step-by-step explanation:

Given that,

The moment of force on a door = 10 N-m

The applied force, F = 2.25 N

We need to find the distance of the handle. The moment of force is given by :

`\tau=F* r`

Where

r is the distance of the handle.

`r=(\tau)/(F)\\\\r=(10)/(2.25)\\\\r=4.44\ m`

So, the required distance is equal to 4.44 m.