Answer:
$9,330.35
Step-by-step explanation:
We'll use the below compound interest formula to solve the problem;
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
Where A = the future amount = $11,000
P = the starting amount(the principal)
r = the interest rate in decimal = 5.5% = 5.5/100 = 0.055
n = number of compounding periods = 12
t = time periods = 3 years
So let's go ahead and substitute the above values into our equation;
![11000=P(1+(0.055)/(12))^(12\ast3)](https://img.qammunity.org/2023/formulas/mathematics/college/rkggfokh1ppvlrxcdxdwkjxz97fy50aebq.png)
We can then evaluate and find P;
![\begin{gathered} 11000=P(1.004583)^(36) \\ 11000=P(1.178949) \\ P=(11000)/(1.178949) \\ \therefore P=9,330.35 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/io3ckf2yfj7dfygn14lacfkclbtgymgfd8.png)
So the amount that should be deposited is $9,330.35