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How much money should be deposited today in an account that earns 5.5% compounded monthly so that it will accumulate to 11,000 in three years?

User Mossman
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1 Answer

5 votes

Answer:

$9,330.35

Step-by-step explanation:

We'll use the below compound interest formula to solve the problem;


A=P(1+(r)/(n))^(nt)

Where A = the future amount = $11,000

P = the starting amount(the principal)

r = the interest rate in decimal = 5.5% = 5.5/100 = 0.055

n = number of compounding periods = 12

t = time periods = 3 years

So let's go ahead and substitute the above values into our equation;


11000=P(1+(0.055)/(12))^(12\ast3)

We can then evaluate and find P;


\begin{gathered} 11000=P(1.004583)^(36) \\ 11000=P(1.178949) \\ P=(11000)/(1.178949) \\ \therefore P=9,330.35 \end{gathered}

So the amount that should be deposited is $9,330.35

User Khriz
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