Question

How many grams of C›H, are needed if 14.38 moles of Oz are used up?(C2H4+302-> 2 CO2+ 2 H20)

Answer 1

`134.21g\text{ of C}_2H_4\text{ is needed}`

Step-by-step explanation:

Here, we want to calculate the mass of ethene needed

From the balanced equation of reaction:

1 mole of ethene needed 3 moles of oxygen

x moles of ethene will need 14.38 moles of oxygen

To get the value of x, we have it that:

`\begin{gathered} 1*14.38\text{ = 3}* x \\ x\text{ = }(14.38)/(3) \\ \\ x\text{ =4.793 moles} \end{gathered}`

To get the mass needed, we have to multiply the number of moles by the molar mass of ethene

The molar mass of ethene is 28 g/mol

Thus, we have the needed mass as:

`\begin{gathered} Mass\text{ = number of moles }*\text{ molar mass} \\ Mass\text{ = 4.793 }*\text{ 28 = 134.21 g} \end{gathered}`