122k views
0 votes
Jenny's school is selling tickets to a play. On the first day of ticket sales the school sold 6 adult tickets and 4 student tickets for a total of $100. The school took in $90 on the second day by selling 5 adult tickets and 5 student tickets. What is the price of one student ticket? $4 $5 $11 $14

1 Answer

3 votes

Given :

The number of tickets sold in the first day : 6 adult tickets and 4 student for a total of $100.

In the second day : 5 adults and 5 students fro $90

Let the price of the adult tickets = x

And the price of the student tickets = y

So, we have the following system of equations :


\begin{gathered} 6x+4y=100\rightarrow(1) \\ 5x+5y=90\rightarrow(2) \end{gathered}

For the question (2), divide all terms by 5 then solve the equation for x


\begin{gathered} (5x)/(5)+(5y)/(5)=(90)/(5) \\ \\ x+y=18 \\ x=18-y \end{gathered}

Substitute with x in the first equation :


\begin{gathered} 6(18-y)+4y=100 \\ 108-6y+4y=100 \\ -2y=100-108 \\ -2y=-8 \\ \\ y=(-8)/(-2)=4 \end{gathered}

So, the price of the student ticket = $4

User Umbrae
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories