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4t -7 < 17 or 7 - 2t >3

User Javiergov
by
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1 Answer

1 vote

Given inequalities are


4t-7<17\text{ or }7-2t>3

Consider


4t-7<17

Adding 7 on both sides, we get


4t-7+7<17+7


4t<24

Dividing both sides by 4, we get


(4t)/(4)<(24)/(4)
t<6

Consider


\text{ }7-2t>3

Subtracting 7 from both sides, we get


\text{ }7-2t-7>3-7


\text{ -}2t>-4

Dividing both sides by (-2), and reverse the inequality since we divide by negative number.


\text{ -}(2t)/(-2)<-(4)/(-2)
t<2

Hence the answer is


t<6\text{ or }t<2
\text{ We know that 2<6, we get t<6.}
t<2<6

The interval notation of the solution is


(-\infty,6)

User Ionelmc
by
8.7k points

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