Answer:
1.1.1. The common difference is 12
1.1.2. The first term is 30
Explanation:
1.1.1. The given quadratic pattern is presented as follows;
The 2nd term = 1
The 3rd term = -16
The 5th term = -14
Let 'd' represent the second difference, we have;
1 + 2d + a = -16
2·d + a = -16 - 1 = -17
2·d + a = -17...(1)
-16 + 3d + a + 4d + a = -14
7·d + 2·a = -14 + 16 = 2
7·d + 2·a = 2...(2)
Making 'a' the subject of both equation (1) and (2) gives;
a = -17 - 2·d
a = 1 - 7/2·d
∴ -17 - 2·d = 1 - 7/2·d
(7/2)·d - 2·d = 1 + 17
(3/2)·d = 18
d = (2/3) × 18 = 12
The common difference, d = 12
a = -17 - 2·d = -17 - 2 × 12 = -41
1.1.2. Let 'x' represent the first term, we have;
x + a + d = 1
x = 1 - (a + d)
x = 1 - (-41 + 12) = 30
The first term, x = 30