176k views
1 vote
How many moles of butane do we have if we have 5.50 x 10^24 molecules of butane (C4H10)?

User KillerFish
by
5.9k points

1 Answer

6 votes

Answer:

9.14moles

Explanations:

According to the Avogadro's constant,


1mole\text{ of }C_4H_(10)=6.02*10^(23)molecules

We are to determine the moles of 5.50 x 10^24 molecules of butane. This is expressed as:


\begin{gathered} mole\text{ of }C_4H_(10)=(5.50*10^(24))/(6.02*10^(23)) \\ mole\text{ of C}_4H_(10)=0.914*10^(24-23) \\ mole\text{ of C}_4H_(10)=0.914*10 \\ mole\text{ of C}_4H_(10)=9.14moles \end{gathered}

Therefore the required mole of butane is 9.14moles

User Alberto
by
5.7k points