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Equations that represent a line which is perpendicular to the line y=-1/8x+3

User Leri
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1 Answer

4 votes

SOLUTION

The equation of a line in slope intercept form is given as


\begin{gathered} y=mx+b \\ where\text{ m is slope and b is intercept on the y-axis } \end{gathered}

Comparing this to


\begin{gathered} y=-(1)/(8)x+3 \\ the\text{ the slope m = -}(1)/(8) \\ and\text{ the intercept b = 3} \end{gathered}

For two lines to be perpendicular, their product of their slope should be = -1

So we have


\begin{gathered} m_1m_2=-1 \\ -(1)/(8)* m_2=-1 \\ m_2=(-1)/(-(1)/(8)) \\ =-1*-(8)/(1) \\ =(8)/(1) \\ =8 \end{gathered}

So the equation of the line becomes


y=8x+3

So the best choice should be one with slope of 8

If you bring 8x to meet y, we have


y-8x=3

So the correct answer is the equation looking like this above

So the best answer is

y - 8x = -2, the last option is the answer

User Djatnieks
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