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Ninety-six percent of the newcomers caviled every time an event was announced. If 140 newcomers did not cavil, how many newcomers were there?

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Given:

a.) Ninety-six percent of the newcomers caviled every time an event was announced.

b.) If 140 newcomers did not cavil.

Let's determine how many newcomers were there,


\text{ Percentage of newcomers who caviled = }\frac{\text{ Total no. - No. of those who didn't caviled}}{\text{ Total number}}\text{ x 100}

Let,

x = Total no. of newcomers

We get,


\text{ 96\% = (}\frac{\text{ x - 140}}{\text{ x }})(\text{100)}
\text{ }\frac{\text{96\% }}{100}\text{= }\frac{\text{ x - 140}}{\text{ x }}
\text{ (0.96)(x) = x - 140}
\text{ 0.96x = x - 140}
\text{ 140 = x - 0}.96\text{x}
\text{ 140 = 0.04x}
\text{ }\frac{\text{140}}{0.04}\text{ = }\frac{\text{0.04x}}{0.04}
\text{ 3,500 = x}

Therefore, there were 3,500 newcomers there.

User Thuy Trinh
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