Question

Write an equation of the line that has a slope of 1/3 and passes through the point (3, 2).

Answer 1

We have to write an equation of a line with a slope of 1/3 and passes through the point (3,2).

We can write the equation in slope-point form:

`y-y_0=m(x-x_0)`

In this case, m=1/3 and (x0,y0)=(3,2). Then, the equation becomes:

`\begin{gathered} y-2=(1)/(3)(x-3) \\ y=(1)/(3)x-1+2 \\ y=(1)/(3)x+1 \end{gathered}`

Answer:

Point-slope form: y-2=(1/3)*(x-3)

Slope-intercept form: y=(1/3)*x+1