Question

Solar radiation at the surface of the earth is about 700 W/m2. How much solar energy is incident on a roof of dimensions 7.48 m by 15.16 m in 1.09 hours?

Answer 1

Given:

The intensity of Solar radiation is,

`I=700\text{ W/m}^2`

The area of the roof is,

`A=7.48\text{ m}*15.16\text{ m}`

The time is,

`\begin{gathered} t=1.09\text{ hours} \\ =1.09*3600\text{ s} \end{gathered}`

To find:

The incident solar energy

Step-by-step explanation:

The incident energy is,

`\begin{gathered} E=IAt \\ =700*7.48*15.16*1.09*3600 \\ =311.5*10^6\text{ J} \end{gathered}`

Hence, the incident energy is

`311.5*10^6\text{ J}`