113k views
3 votes
8. Find the slope of the line containing the points (-3,-3) and (-2,1).

1 Answer

1 vote

Slope is:


m=(y_2-y_1)/(x_2-x_1)

At the point (-3,-3) and (-2,1).

so:


\begin{gathered} x_1=-3 \\ y_1=-3 \\ x_2=-2 \\ y_2=1 \end{gathered}

so the slope is:


\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(1-(-3))/((-2)-(-3)) \\ m=(1+3)/(-2+3) \\ m=(4)/(1) \\ m=4 \end{gathered}

slope of the line is 4.

User Krasimir
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories