Question

8. Find the slope of the line containing the points (-3,-3) and (-2,1).

Answer 1

Slope is:

`m=(y_2-y_1)/(x_2-x_1)`

At the point (-3,-3) and (-2,1).

so:

`\begin{gathered} x_1=-3 \\ y_1=-3 \\ x_2=-2 \\ y_2=1 \end{gathered}`

so the slope is:

`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(1-(-3))/((-2)-(-3)) \\ m=(1+3)/(-2+3) \\ m=(4)/(1) \\ m=4 \end{gathered}`

slope of the line is 4.