So we have to factor this expression:
![-(1)/(3)x+(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/lhxdp8ef531lurt40f1pukc8hh5v3ivjg9.png)
Using the leading coefficient of the variable term. The variable term is that with x and the leading coefficient is the number multiplying the x, in this case:
![-(1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/getquuff49cohne05n98hv73iv77n9lzv4.png)
What we are going to do now is take the term that is not the variable term and multiply and divide it by the leading coefficient:
![\begin{gathered} (2)/(3)=(2)/(3)\cdot(-(1)/(3))/(-(1)/(3))=(2)/(3)\cdot(-(1)/(3))\cdot(-(3)/(1))=(2)/(3)\cdot(-3)\cdot(-(1)/(3)) \\ (2)/(3)=(-2)\cdot(-(1)/(3)) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/93o35m6w2hsqkm86o4egufp297lswtxj3o.png)
Then we get:
![-(1)/(3)x+(2)/(3)=-(1)/(3)x+(-2)\cdot(-(1)/(3))](https://img.qammunity.org/2023/formulas/mathematics/college/1wgozvrj2ay8oxtqro97j8s1c8sztv1pf4.png)
Now that both terms are multiplied by the same number we can factor the expression:
![-(1)/(3)x+(-2)\cdot(-(1)/(3))=-(1)/(3)\cdot(x-2)](https://img.qammunity.org/2023/formulas/mathematics/college/edl8w5een7whuur7lozzjts6dwjb5a208m.png)
Then the answer is:
![-(1)/(3)\cdot(x-2)](https://img.qammunity.org/2023/formulas/mathematics/college/3aiiu1udbspb7qxzo9aecfg9s4ujpr732z.png)