Question

Question 2 part b complete the square to rewrite the following equation into standard form show all work X^2+6x+y2-4y=-9

Answer 1

Step-by-step explanation

We are to write the equation of the circle in standard form

Given theequation:

`x^2+6x+y^2-4y=-9`
`\left(x−a\right)^2+\left(y−b\right)^2=r^2\:\:\mathrm{is\:the\:circle\:equation\:with\:a\:radius\:r,\:centered\:at}\:\left(a,\:b\right)`

Using completing the square method

`\left(x-\left(-3\right)\right)^2+\left(y-2\right)^2=2^2`

Thus, we will have the answer to be

`(x+3)^2+(y-2)^2=2^2`

Where

`\begin{gathered} (a,b)=(-3,2) \\ r=2 \end{gathered}`