24.2k views
2 votes
Given the following table of grades from Mrs. Hardcase's English classes:Write the notation, then answer as a fraction, decimal percent3. What is the probability that a randomly selected student got a A or B?4. What is the probability that an "A" student is male?P(male A)5. What is the probability that if a student was female that they got a passing grade?P(passing grade | female)6. What is the probability of a male student given that they failed?P()7. What is the probability of a randomly selected student is male?P()8. What is the probability of a female student given that they got a "B"?P()9. What is the probability of a randomly selected student passing Mrs. Hardcase's class PC)

Given the following table of grades from Mrs. Hardcase's English classes:Write the-example-1
User Durga
by
7.8k points

1 Answer

1 vote

Answer:

• 3. 0.35

,

• 4. 0.6

,

• 5. 19/22

,

• 6. 7/13

,

• 7. 0.56

,

• 8. 0.6

,

• 9. 0.87

Explanation:

Part 3

The total number of students = 100

• The number of students who had a grade of A = 20

,

• The number of students who had a grade of B = 15

The probability that a randomly selected student got an A or B:


P(A\text{ or B)=P(A)+P(B)}=(20)/(100)+(15)/(100)=(35)/(100)=0.35

The probability that a randomly selected student got an A or B is 0.35.

Part 4

The number of male students who scored an A = 12.


P(\text{male}|A)=\frac{P(\text{male and scored A)}}{P(scored\text{ A)}}=((12)/(100))/((20)/(100))=(12)/(20)=0.6

The probability that an "A" student is male is 0.6.

Part 5

The passing grades are A, B, C, and D.

• The number of females who had a passing grade = 8+9+13+8 = 38

• The number of females = 44


\begin{gathered} P(\textpassing grade\frac{\text{P(passing grade and female)}}{P(female)} \\ =(38)/(100)/(44)/(100) \\ =(38)/(44) \\ =(19)/(22) \end{gathered}

The probability that if a student was female that they got a passing grade is 19/22.

Part 6

The probability of a male student given that they failed.

• The number of students who failed = 7+6 = 13

,

• The number of male students who failed = 7


P(\textmale student=(7)/(13)

The probability of a male student given that they failed is 7/13.

Part 7

• The total number of students = 100

,

• The number of male students = 56.


P(\text{male)}=(56)/(100)=0.56

The probability of a randomly selected student being male is 0.56.

Part 8

• The number of female students that got a B = 9.

,

• The number of students that got a B = 15


P(\text{female}|B)=(9)/(15)=0.6

The probability of a female student given that they got a "B" is 0.6.

Part 9

The number of students who passed Mrs. Hardcase's class = 100-13=87


P(\text{passing)}=(87)/(100)=0.87

The probability of a randomly selected student passing Mrs. Hardcase's class is 0.87.

User Ooberdan
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories