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√(48)

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In order to solve this exercise, you need to use the following property of Radicals:


\sqrt[n]{b^n}=b^{(n)/(n)}=b^1=b

Given:


\sqrt[]{48}

The first step is to descompose the Radicand (in this case it is 48) into its prime factors:


48=2\cdot2\cdot2\cdot2\cdot3=2^4\cdot3

Rewrite the Radicand:


undefined

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