Question

I need help with
`√(48)`

Answer 1

In order to solve this exercise, you need to use the following property of Radicals:

`\sqrt[n]{b^n}=b^{(n)/(n)}=b^1=b`

Given:

`\sqrt[]{48}`

The first step is to descompose the Radicand (in this case it is 48) into its prime factors:

`48=2\cdot2\cdot2\cdot2\cdot3=2^4\cdot3`

Rewrite the Radicand: