Question

To prepare a fertilizer, an engineer dilutes a stock solution of sulfuric acid by adding 25.0 m3of 7.50 M acid to enough water to make 500. m3. What is the mass (in g) of sulfuric acid per milliliter of the diluted solution?

Answer 1

We have the volume and the concentration of sulfuric acid, and we can find the number of moles of sulfuric acid, using the following formula:

`M=(n)/(V)\begin{cases}M=\text{concentration} \\ n=\text{moles} \\ V=\text{volume}\end{cases},`

We clear the number of moles and replace the given data:

`n=M\cdot V=7.50\cdot25000L=187500\text{ moles.}`

Remember that a cubic meter equals 1000 liters.

Using the molar mass of sulfuric acid, we can obtain its