Question

A planet was discovered by the Kepler space telescope. The planet had a mass of8.0 x 10^27kg and a radius of 1.0 x 10^8m. What is the value of the acceleration due to gravity on the surface of the planet?

Answer 1

`g=53.36\ m/s^2`

Step-by-step explanation:

Given that,

The mass of the planet,
`M=8* 10^(27)\ kg`

The radius of the planet,
`R=10^8\ m`

We need to find the value of the acceleration due to gravity on the surface of the planet. The formula for the acceleration due to gravity is given by :

`g=(GM)/(R^2)\\\\g=(6.67* 10^(-11)* 8* 10^(27))/((10^8)^2)\\\\g=53.36\ m/s^2`

So, the value of acceleration due to gravity on the surface of the plate is equal to
`53.36\ m/s^2`.