What are the [H+] and [OH-] for a substance with a pH of 9.2? Show work please

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16 votes

Step-by-step explanation:

[H+]=10^-pH

[H+]=10^-9.2

[H+]=6.031x10^-10

[OH-]=1x10^-14÷[H+]

[OH-]=1x10^-14÷[6.031x10^-10]

[OH-]= 1.66x10^-5

im pretty sure this is right

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