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The vertices of ABC are A(2,-5), B(-3, - 1), and C(3,2). For the translation below, give the vertices of AA'B'C'. T * - 1) (ABC) The vertices of AA'B'C' are A'B', and c'| (Simplify your answers. Type ordered pairs.)

The vertices of ABC are A(2,-5), B(-3, - 1), and C(3,2). For the translation below-example-1
User Corion
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In order to calculate the translation of <-4, -1> to the triangle ABC, we just need to add these coordinates to all vertices of the triangle, that is, add -4 to the x-coordinate and -1 to the y-coordinate. So we have that:


\begin{gathered} A(2,-5)\to A^(\prime)(2-4,-5-1)=A^(\prime)(-2,-6) \\ B(-3,-1)\to B^(\prime)(-3-4,-1-1)=B^(\prime)(-7,-2) \\ C(3,2)\to C^(\prime)(3-4,2-1)=C^(\prime)(-1,1) \end{gathered}

So the vertices after the translation are A'(-2, -6), B'(-7, -2) and C'(-1, 1).

User Mayvas
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