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1 vote
Compute.
\[ \left(\dfrac 8 3\right)^{-2} \cdot \left(\dfrac 3 4\right)^{-3}\]

User Alaboudi
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1 Answer

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\left(\cfrac{8}{3}\right)^(-2) \left(\cfrac{3}{4}\right)^(-3)\implies \left(\cfrac{3}{8}\right)^(+2) \left(\cfrac{4}{3}\right)^(+3)\implies \cfrac{3^2}{8^2}\cdot \cfrac{4^3}{3^3}\implies \cfrac{4^3}{8^2}\cdot \cfrac{3^2}{3^3} \\\\\\ \cfrac{64}{64}\cdot \cfrac{1}{3}\implies 1\cdot \cfrac{1}{3}\implies \cfrac{1}{3}

User Fozziethebeat
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