The likelihood that offspring from two heterozygous monsters will have three eyes is 6.25%, as deduced by using a Punnett square to understand the genetic inheritance of the eye shape trait.
The student inquires about the likelihood that offspring will have three eyes from two monsters who are heterozygous for eye shape, with the understanding that two eyes are dominant to three eyes. This is a problem of genetic inheritance and can be explained by creating a Punnett square for a single trait cross with heterozygous parents (Aa x Aa).
In this scenario, both parents have the genotype Aa for the trait, where 'A' represents the allele for two eyes (dominant) and 'a' represents the allele for three eyes (recessive). When each parent can contribute either a dominant or a recessive allele, the possible combinations in the offspring are AA, Aa, aA, and aa.
The only genotype that would result in three eyes (since two eyes are dominant) is aa. Each parent has a 1 in 4 chance of passing on the 'a' allele, so the probability of getting 'aa' for three eyes in the offspring is 1/4 * 1/4, which is 1/16 or 6.25%.
So, there is a 6.25% chance that the offspring of two heterozygous monsters will have three eyes.