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Consider a set of data in which the sample mean is 23.8 and the sample standard deviation is 6.6. Calculate the z score given that x= 26.7 round your answer two decimal places.

Consider a set of data in which the sample mean is 23.8 and the sample standard deviation-example-1
User Jbcedge
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SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given data


\begin{gathered} mean(\mu)=23.8 \\ standard\text{ }deviation(\sigma)=6.6 \\ x=26.7 \end{gathered}

STEP 2: Write the formula for calculating z-scores


z=(x-\mu)/(\sigma)

By substitution,


\begin{gathered} z=(26.7-23.8)/(6.6)=(2.9)/(6.6)=0.43939393939 \\ \\ z\approx0.44 \end{gathered}

Hence, the z score is approximately 0.44 to 2 decimal places

User David Carmo
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